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Remove OPENSSL_zalloc helper

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This function is not needed, because in each case it is used, we follow
it up immediately with an initialization function call. This means that
the zeroing here is unneeded, since the initialization already
guarantees things end up in the right state.

It also swaps the reset call with a simpler init call, also because
reset is implemented as init with a return value that is always 1. That
means the more complex logic is not needed at all.

Signed-off-by: Dirkjan Bussink <d.bussink@gmail.com>
Reviewed-by: Jakub Jelen <jjelen@redhat.com>
This commit is contained in:
Dirkjan Bussink
2020-12-12 17:23:07 +01:00
committed by Jakub Jelen
parent ba88e0fba5
commit d1806a523c
1 changed files with 8 additions and 16 deletions
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24
src/libcrypto-compat.c
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@@ -16,15 +16,6 @@
#include <openssl/engine.h>
#endif
static void *OPENSSL_zalloc(size_t num)
{
void *ret = OPENSSL_malloc(num);
if (ret != NULL)
memset(ret, 0, num);
return ret;
}
int RSA_set0_key(RSA *r, BIGNUM *n, BIGNUM *e, BIGNUM *d)
{
/* If the fields n and e in r are NULL, the corresponding input
@@ -236,7 +227,7 @@ int ECDSA_SIG_set0(ECDSA_SIG *sig, BIGNUM *r, BIGNUM *s)
EVP_MD_CTX *EVP_MD_CTX_new(void)
{
EVP_MD_CTX *ctx = OPENSSL_zalloc(sizeof(EVP_MD_CTX));
EVP_MD_CTX *ctx = OPENSSL_malloc(sizeof(EVP_MD_CTX));
if (ctx != NULL) {
EVP_MD_CTX_init(ctx);
}
@@ -292,13 +283,10 @@ int EVP_CIPHER_CTX_reset(EVP_CIPHER_CTX *ctx)
HMAC_CTX *HMAC_CTX_new(void)
{
HMAC_CTX *ctx = OPENSSL_zalloc(sizeof(HMAC_CTX));
HMAC_CTX *ctx = OPENSSL_malloc(sizeof(HMAC_CTX));
if (ctx != NULL) {
if (!HMAC_CTX_reset(ctx)) {
HMAC_CTX_free(ctx);
return NULL;
}
HMAC_CTX_init(ctx);
}
return ctx;
}
@@ -335,7 +323,11 @@ int HMAC_CTX_reset(HMAC_CTX *ctx)
#ifndef HAVE_OPENSSL_EVP_CIPHER_CTX_NEW
EVP_CIPHER_CTX *EVP_CIPHER_CTX_new(void)
{
return OPENSSL_zalloc(sizeof(EVP_CIPHER_CTX));
EVP_CIPHER_CTX *ctx = OPENSSL_malloc(sizeof(EVP_CIPHER_CTX));
if (ctx != NULL) {
EVP_CIPHER_CTX_init(ctx);
}
return ctx;
}
void EVP_CIPHER_CTX_free(EVP_CIPHER_CTX *ctx)