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net: small bug on rxhash calculation
[ Upstream commit 6862234238 ]
In the current rxhash calculation function, while the
sorting of the ports/addrs is coherent (you get the
same rxhash for packets sharing the same 4-tuple, in
both directions), ports and addrs are sorted
independently. This implies packets from a connection
between the same addresses but crossed ports hash to
the same rxhash.
For example, traffic between A=S:l and B=L:s is hashed
(in both directions) from {L, S, {s, l}}. The same
rxhash is obtained for packets between C=S:s and D=L:l.
This patch ensures that you either swap both addrs and ports,
or you swap none. Traffic between A and B, and traffic
between C and D, get their rxhash from different sources
({L, S, {l, s}} for A<->B, and {L, S, {s, l}} for C<->D)
The patch is co-written with Eric Dumazet <edumazet@google.com>
Signed-off-by: Chema Gonzalez <chema@google.com>
Signed-off-by: Eric Dumazet <edumazet@google.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
committed by
Greg Kroah-Hartman
parent
0ddaf88b27
commit
74665a9b4f
@@ -2559,16 +2559,17 @@ __u32 __skb_get_rxhash(struct sk_buff *skb)
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poff = proto_ports_offset(ip_proto);
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if (poff >= 0) {
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nhoff += ihl * 4 + poff;
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if (pskb_may_pull(skb, nhoff + 4)) {
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if (pskb_may_pull(skb, nhoff + 4))
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ports.v32 = * (__force u32 *) (skb->data + nhoff);
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if (ports.v16[1] < ports.v16[0])
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swap(ports.v16[0], ports.v16[1]);
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}
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}
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/* get a consistent hash (same value on both flow directions) */
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if (addr2 < addr1)
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if (addr2 < addr1 ||
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(addr2 == addr1 &&
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ports.v16[1] < ports.v16[0])) {
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swap(addr1, addr2);
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swap(ports.v16[0], ports.v16[1]);
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}
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hash = jhash_3words(addr1, addr2, ports.v32, hashrnd);
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if (!hash)
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