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Btrfs: return gracefully from balance if fs tree is corrupted
commit 3561b9db70 upstream.
When relocating tree blocks, we firstly get block information from
back references in the extent tree, we then search fs tree to try to
find all parents of a block.
However, if fs tree is corrupted, eg. if there're some missing
items, we could come across these WARN_ONs and BUG_ONs.
This makes us print some error messages and return gracefully
from balance.
Signed-off-by: Liu Bo <bo.li.liu@oracle.com>
Reviewed-by: Josef Bacik <jbacik@fb.com>
Signed-off-by: David Sterba <dsterba@suse.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
committed by
Greg Kroah-Hartman
parent
78a587c608
commit
8ca6845a58
@@ -921,9 +921,16 @@ again:
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path2->slots[level]--;
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eb = path2->nodes[level];
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WARN_ON(btrfs_node_blockptr(eb, path2->slots[level]) !=
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cur->bytenr);
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if (btrfs_node_blockptr(eb, path2->slots[level]) !=
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cur->bytenr) {
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btrfs_err(root->fs_info,
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"couldn't find block (%llu) (level %d) in tree (%llu) with key (%llu %u %llu)",
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cur->bytenr, level - 1, root->objectid,
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node_key->objectid, node_key->type,
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node_key->offset);
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err = -ENOENT;
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goto out;
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}
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lower = cur;
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need_check = true;
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for (; level < BTRFS_MAX_LEVEL; level++) {
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@@ -2676,11 +2683,15 @@ static int do_relocation(struct btrfs_trans_handle *trans,
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if (!upper->eb) {
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ret = btrfs_search_slot(trans, root, key, path, 0, 1);
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if (ret < 0) {
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err = ret;
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if (ret) {
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if (ret < 0)
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err = ret;
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else
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err = -ENOENT;
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btrfs_release_path(path);
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break;
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}
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BUG_ON(ret > 0);
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if (!upper->eb) {
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upper->eb = path->nodes[upper->level];
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